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Question

If f(x)=1x+x2x3+x15+x16x17, then the coefficient of x2 in f(x1) is

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Solution

f(x)=1x+x2x3+x15+x16x17
f(x)=1x181+x
f(x1)=1(x1)181+(x1)
Therefore, required coefficient of x2 is equal to the coefficient of x3 in 1(1x)18, which is given by 18C3=816

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