CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If $$f(x)$$ $$=\begin{cases} 2x+1; \ x\leq0\\x^2; \  x>0\end{cases}$$, then the values of $$f(-1),f(1)$$  are


A
1,1
loader
B
1,1
loader
C
1,1
loader
D
1,1
loader

Solution

The correct option is A $$-1,1$$
$$f(x)=2x+1$$
$$f(-1)=2(-1)+1$$ ; since $$x<0$$
      $$=-1$$
$$f(1)=(1)^2=1$$; since $$x>0$$

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image