Question

# If $$f(x)$$ $$=\begin{cases} 2x+1; \ x\leq0\\x^2; \ x>0\end{cases}$$, then the values of $$f(-1),f(1)$$  are

A
1,1
B
1,1
C
1,1
D
1,1

Solution

## The correct option is A $$-1,1$$$$f(x)=2x+1$$ $$f(-1)=2(-1)+1$$ ; since $$x<0$$      $$=-1$$$$f(1)=(1)^2=1$$; since $$x>0$$Maths

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