If f(x) = cos [e] x + cos [–e] x, then f(π) = ___________.

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Solution

Given: f(x) = cos[e]x + cos[–e]x

$f (x) = \cos [e] x + \cos [- e] x = \cos 2 x + \cos (- 3 x) (∵ e = 2.718 approx) = \cos 2 x + \cos 3 x \Rightarrow f (π) = \cos 2 π + \cos 3 π = 1 - 1 = 0$

Hence, f(π) = 0.

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