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Question

If f(x)=xat3etdt, then the value of df(x)dx is

A
ex(x3+3x2)
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B
x3ex
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C
e3ea
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D
None of these
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Solution

The correct option is B x3ex
f(x)=xat3etdt=0at3.etdt+x0t3etdtdf(x)dx=ddx(0at3.etdt)+ddx(x0t3.etdt)df(x)dx=0+x3ex=x3ex

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