Given, f(x)=2x+p
⇒y=2x+p⇒y−p=2x
⇒x=y−p2
⇒f−1(x)=x−p2 ....(i)
Given, f−1(x)=m(4x+3)=4mx+3m ....(ii)
Comparing (i) and (ii), we get
x2−p2=4mx+3m⇒4m=12⇒m=18⇒−p2=3m⇒−p2=38⇒p=−34