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Question

If f:x2x+p and f1:(x)m(4x+3), where p and m are some constants, find the values of p and m.

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Solution

Given, f(x)=2x+p

y=2x+pyp=2x

x=yp2

f1(x)=xp2 ....(i)

Given, f1(x)=m(4x+3)=4mx+3m ....(ii)

Comparing (i) and (ii), we get

x2p2=4mx+3m4m=12m=18p2=3mp2=38p=34


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