wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x)=(x2)3 is a function defined in RR, then

A
f1(x)=(x2)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
f1(x)=3x+2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
f1(x)=3x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
f1(x) does not exist
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B f1(x)=3x+2

This function passes the horizontal line test which means it is a one to one function also it is an onto function, since it is cubic. So f(x) is invertible.
f(x)=(x2)3y=(x2)3
Switch x and y
x=(y2)33x=y2y=3x+2
Replace y with f1(x)
f1(x)=3x+2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon