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Question

If for a binomial distribution mean is 103 and sum of mean and variance is 409. Then the parameters are

A
23,10
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B
23,20
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C
5,23
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D
4,23
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Solution

The correct option is C 5,23
Mean =np=103
Variance =npq=409
The sum of Mean and variance,
np+np(1p)=409
np(2p)=409
103(2p)=409
2p=43
p=23
Hence, n=5

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