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Question

If for the differential equation y1=yx+ϕ(xy) the general solution is y=xlog|Cx| then ϕ(xy)is given by

A
x2y2
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B
y2x2
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C
x2y2
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D
y2x2
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Solution

The correct option is D y2x2
Putting so that xdvdx+v=dydx, we have
xdvdx+v=v+ϕ(1v)dvϕ(1v)=dxx
log|Cx|=dvϕ(1v) (being constant of integration.)
But y=xlog|Cx| is the general solution so
xy=1v=dvϕ(1v)ϕ(1v)=1v2ϕ(xy)=y2x2

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