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Question

If 2m+n2nm=16,3p3n=81 and a=2110, then a2m+np(am2n+2p)1=


  1. 14

  2. 18

  3. 2

  4. 9


Solution

The correct option is

2m+n2nm=16,3p3n=81 and a=2110, then a2m+np(am2n+2p)12m+nn+m=2422m=24Comparing, we get2m=4m=42=2Given,3p3n=813pn=(3)4pn=4a2m+np(am2n+2p)1=a2m+np×am2n+2p=a2m+np+m2n+2p=a3mn+pa=2110=(2110)3mn+p=23mn+p10=23×2n+p10=26n+p10=26+410=21010=2

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