Question

If $\frac{3}{5}$ of a number exceeds its $\frac{2}{7}$ by 44, find the number. [4 MARKS]

Answer 1

Concept : 1 Mark
Simplification : 2 Marks
Conclusion : 1 Mark

Let the number be $x$
then$\frac{3}{5}$ of a number $=\frac{3}{5}x$
$\frac{2}{7}$ of a number $=\frac{2}{7}x$
Then,$\frac{3}{5}x-\frac{2}{7}x=44$
$\frac{3x}{5}-\frac{2x}{7}=44$
$\frac{21x-10x}{35}=44$
$11x=44\times 35$
$x=\frac{44\times 35}{11}$
$x=140$
Hence, the number is 140.