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Question

If c+ici = a+ib, where a,b,c are real, then a2+b2 =


A

1

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B

-1

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C

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D

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Solution

The correct option is A

1


c+ici = a+ib .........(i)

cic+i = a-ib .........(ii)

Multiplying (i) and (ii), we get

c2+1c2+1=a2+b2a2+b2=1.


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