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Question

If xy+yx=1, where x,y 0 then the value of (x3y3) is 
(a) 1 (b)-1 (c) 0 (d) 12


Solution

ANSWER:
(c) 0
xy+yx=1

x2+y2xy=1
x2+y2=xy
x2+y2+xy=0

(x3y3)=(x+y) (x2+y2+xy)=0


Mathematics
Secondary School Mathematics IX
Standard IX

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