Question

If G.M.=18 and A.M.=27,then H.M. is

• A. $\frac{1}{18}$
• B. $\frac{1}{12}$
• C. 12
• D. $9\sqrt{6}$

Answer 1

Answer: (C)

12

We have,

$G.M=18$

$A.M=27$

$H.M=?$

We know that

${(G.M)}^2=(A.M)(H.M)$

Therefore,

${\left(18\right)}^2=27\times H.M$

$H.M=\frac{18\times 18}{27}$

$H.M=\frac{18\times 2}{3}$

$H.M=6\times 2$

$H.M=12$

Hence, this is the answer.