If - apparent of a liquid in a vessel is 76

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Expansion In Liquids and Gases

If γ appare...

Question

If $γ$ (apparent) of a liquid in a vessel is $76$ % of $γ$ (real) of that liquid, the coefficient of linear expansion of the vessel is

8

% of

γ

(real)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16

% of

γ

(real)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

% of

γ

(real)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25.3

% of

γ

(real)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $8$ % of $γ$ (real)
$γ_{a} = γ_{r} - γ_{g}$
$\frac{76}{100} γ_{r} = γ_{r} - γ_{g}$
$\Rightarrow \frac{24}{100} γ_{r} = γ_{g}$
$α_{g} = \frac{1}{3} \times \frac{24}{100} γ_{r} = \frac{24}{300} γ_{r} = 0.08 \times γ_{r}$ which is $8 %$ of $γ_{r}$

Suggest Corrections

Similar questions

(1): when a liquid with a coefficient of $γ$ is heated in a vessel of a coefficient of linear expansion $\frac{γ}{3}$ , the level of liquid in the vessel remains unchanged.

(2): $γ_{a} = γ_{r} - γ_{g} = γ_{r} - 3 α = 0$

The co-efficient of real expansion of liquid is $γ_{r}$ and the co-efficient of apparent expansions of the liquid is $γ_{a}$ . The co-efficient of cubical expansion of the vessel is $γ$ . If $γ_{r} : γ_{a} = 4 : 1$ then $γ_{a} : γ$ is :

If d1 and d2 are the densities of a liquid at $t_{1}^{0} C$ and $t_{2}^{0} C$ , then $\frac{d_{1}}{d_{2}}$ is ( $γ$ = coefficient of real expansion)

If $γ$ is the coefficient of a real expansion of a liquid then the temperature at which density of a liquid is 1% of its density at 0 $^{o}$ C is :

Q. On heating a liquid of cubical expansion

γ

in a container having coefficient of linear expansion

\frac{γ}{3}

, the level of liquid in the container will:

Join BYJU'S Learning Program

If γ (apparent) of a liquid in a vessel is 76% of γ (real) of that liquid, the coefficient of linear expansion of the vessel is

The correct option is B 8% of γ (real)γa=γr−γg76100γr=γr−γg⇒24100γr=γgαg=13×24100γr=24300γr=0.08×γr which is 8% of γr

If $γ$ (apparent) of a liquid in a vessel is $76$ % of $γ$ (real) of that liquid, the coefficient of linear expansion of the vessel is

The correct option is B $8$ % of $γ$ (real)
$γ_{a} = γ_{r} - γ_{g}$
$\frac{76}{100} γ_{r} = γ_{r} - γ_{g}$
$\Rightarrow \frac{24}{100} γ_{r} = γ_{g}$
$α_{g} = \frac{1}{3} \times \frac{24}{100} γ_{r} = \frac{24}{300} γ_{r} = 0.08 \times γ_{r}$ which is $8 %$ of $γ_{r}$