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Question

IfH1,H2,....H20be 20 harmonic means between 2 and 3, thenH1+2H12+H20+3H203=


A

20

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B

21

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C

40

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D

38

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Solution

The correct option is C

40


H1+2H12+H20+3H203=12+1H1121H1+13+1H20131H20

=12+12+d12d12+13+13d13+d13

22+dd+23dd

231d2

=2×212[as also,13=12+21d]
=40


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