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Question

If H1,H2,...,H20 harmonic means between 2 and 3, then H1+2H12+H20+3H203=

A
20
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B
21
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C
40
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D
38
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Solution

The correct option is C 40
Given,
The sequence is in harmonic progression between 2 and 3 and n=20

Now,
d=1b1an+1=131320+1=1126
1H1=1a+d=121126=62126
H1=12662

Similarly,
H2O=1a+20d
H1+2H22+H2O+3H2O3=12662+2126622+12643+3d126433
=125+(85)=40

Hence,
Option C is correct answer.

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