If H is the head over the crest of a rectangular weir, the discharge varies as:

H

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H^{0.5}

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H^{1.5}

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H^{2.5}

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Solution

The correct option is C $H^{1.5}$
Expression for discharge over crest of rectangular weir

$Q = \frac{2}{3} C_{d} \times L \times \sqrt{2 g} H^{\frac{3}{2}}$

$Q = {kH}^{\frac{3}{2}}$

$Hence, Q \propto H^{1.5}$

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If H is the head over the crest of a rectangular weir, the discharge varies as:

The correct option is C H1.5Expression for discharge over crest of rectangular weir Q=23Cd×L×√2gH32 Q= kH32 Hence, Q∝H1.5

The correct option is C $H^{1.5}$
Expression for discharge over crest of rectangular weir

$Q = \frac{2}{3} C_{d} \times L \times \sqrt{2 g} H^{\frac{3}{2}}$

$Q = {kH}^{\frac{3}{2}}$

$Hence, Q \propto H^{1.5}$