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Question

If in a Δ ABC, a2+b2+c2=8R2, where R = circumradius, then the triangle is


A

equilateral

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B

isosceles

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C

right angled

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D

No such triangle exists

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Solution

The correct option is C

right angled


a2+b2+c2=8R2sin2A+sin2B+sin2C=2cos2A+cos2B+cos2C+1=04cosA.cosB.cosC=0A or B or C=π2


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