If in a parallelogram $A B C D$ , the coordinate of $A, B$ and $C$ are respectively $(1, 2), (3, 4)$ and $(2, 5)$ , then the equation of the diagonal $B D$ is:-

5 x + 3 y - 11 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x - 5 y + 7 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x + 5 y - 13 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 x - 3 y + 9 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $5 x - 3 y + 9 = 0$

Let let coordinates of D are $X$ and $Y$ then $X + 3 = 3, Y + 4 = 7$

$X = 0, Y = 3$

Only above coordinates statisfied by $5 x - 3 y + 9 = 0$

Suggest Corrections

Similar questions

A B D C

A, B

C

(1, 2), (3, 4)

(2, 5)

A D

The equation of the line passing through $(1, 5)$ and perpendicular to the line $3 x - 5 y + 7 = 0$ is

3 x + 5 y = 19

(3, 2)

7 x + 5 y - 3 z = 16

3 x - 5 y + 2 z = - 8

5 x + 3 y - 7 z = 0

Join BYJU'S Learning Program