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Standard XII

Mathematics

Axiomatic Approach

If in a rando...

Question

If in a random experiment the probability of getting a success is twice that of a failure, then the probability of getting $6$ successes in $10$ trials is

^{10} C_{6} {(\frac{1}{3})}^{6} {(\frac{2}{3})}^{4}

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^{10} C_{6} {(\frac{2}{3})}^{6} {(\frac{1}{3})}^{4}

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^{10} C_{6} {(\frac{1}{4})}^{6} {(\frac{3}{4})}^{4}

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^{10} C_{6} {(\frac{3}{4})}^{6} {(\frac{1}{4})}^{4}

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Solution

The correct option is A $^{10} C_{6} {(\frac{2}{3})}^{6} {(\frac{1}{3})}^{4}$
Probability of success $= \frac{2}{3}$
Probability of failure $= 1 - \frac{2}{3} = \frac{1}{3}$
Probability of getting 6 successes in 10 trials is $=^{10} C_{6} {(\frac{2}{3})}^{6} {(\frac{1}{3})}^{4}$

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If in a random experiment the probability of getting a success is twice that of a failure, then the probability of getting 6 successes in 10 trials is

The correct option is A 10C6(23)6(13)4Probability of success=23Probability of failure =1−23=13Probability of getting 6 successes in 10 trials is =10C6(23)6(13)4

If in a random experiment the probability of getting a success is twice that of a failure, then the probability of getting $6$ successes in $10$ trials is

The correct option is A $^{10} C_{6} {(\frac{2}{3})}^{6} {(\frac{1}{3})}^{4}$
Probability of success $= \frac{2}{3}$
Probability of failure $= 1 - \frac{2}{3} = \frac{1}{3}$
Probability of getting 6 successes in 10 trials is $=^{10} C_{6} {(\frac{2}{3})}^{6} {(\frac{1}{3})}^{4}$