Question

# If in a right triangle, the hypotenuse is 20 m and the difference between the lengths of other sides is 4 m. Then, the sides are 14 and 18. False True

Solution

## The correct option is A False Let other two sides of right triangle be x and x + 4, then x2+(x+4)2=202 2x2+8x+16=400 2x2+8x−384=0 x2+4x−192=0 Solving this equation, we get x = 12 or – 16 Let's consider only positive value for length The two sides are 12 m and 12 + 4 or 16 m.

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