CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If in a vernier caliper 10 VSD coincides with 8 MSD, then the least count of vernier caliper is (given 1 MSD = 1 mm)

Open in App
Solution

Step 1: Given data:

In the vernier callipers

10 VSD= 8 MSD

Where VSD= Vernier scale division

And, MSD= Main scale division

1 MSD = 1mm

Step 2: Calculation of the least count of the vernier callipers:

The least count of vernier callipers or vernier constant is given by;

Least count= Vernier constant = 1 MSD 1 VSD

Since,

10 VSD= 8 MSD

1 VSD= 810 MSD

1 VSD= 0.8 MSD

Now,

Least count= 1 MSD 0.8 MSD

= 0.2 MSD

But, 1 MSD= 1mm

Therefore the least count of the vernier callipers will be

= 0.2×1mm

= 0.2mm

Thus,

The least count of the vernier callipers is 0.2mm


flag
Suggest Corrections
thumbs-up
89
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon