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Question

If, in the first orbit of a hydrogen atom, the total energy of the electron is 21.76×1019J, then the electric potential energy of an electron belonging to the second orbit of the same atom, will be,

A
10.88×1019 J
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B
5.44×1019 J
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C
21.76×1019 J
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D
43.52×1019 J
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Solution

The correct option is A 10.88×1019 J
The total energy of an electron, in hydrogen atom is,
En=me48ϵ20h2n2

En1n2

E1E2=n22n21

21.76×1019E2=41

E2=5.44×1019 J

Now, potential energy and total energy are related as,
|P.E.|=2|T.E.|

|P.E|=2|5.44×1019|=10.88×1019 J

P.E.=10.88×1019 J

Hence, (A) is the correct answer.

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