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Question

If g(x)dx=g(x), then g(x){f(x)+f(x)}dx is equal to


A

g(x)f(x)g(x)f(x)+C

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B

g(x)f(x)+C

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C

g(x)f(x)+C

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D

g(x)f2(x)+C

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Solution

The correct option is C

g(x)f(x)+C


g(x){f(x)+f(x)}dx
=g(x)f(x)dx+g(x)f(x)dx
=f(x)(g(x)dx)(f(x)g(x)dx)dx+g(x)f(x)dx
=f(x)g(x)g(x)f(x)dx+g(x)f(x)dx+C ( g(x)dx=g(x))
=f(x)g(x)+C


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