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Question

If intensity of radiation incident on a photocell be increased four times keeping frequency constant, then number of photoelectrons and energy of photoelectrons emitted become

A
Four times, doubled
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B
Doubled, remains unchanged
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C
Remains unchanged, doubled
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D
Four times, remains unchanged
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Solution

The correct option is B Four times, remains unchanged
Number of photoelectrons emitted Intensity of radiation energy of photoelectrons
Energy of photoelectrons emitted Frequency
So, number of photoelectrons emitted becomes four times but energy of photoelectrons remains same.

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