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Question

If is found, on heating a gas, its volume increase by 50% and pressure decreases to 60% of its original value. If the original temperature was15C, find the temperature to which is was heated?

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Solution

The gas has constant mass as it is ideal. So we can use the equation for the general transformation of the ideal gas:
The mixed gas formula: P1V1T1=P2V2T2

Given: T1 = -15°C+273 = 258 K

Assume: P1P_1P1 = P atm and P2P_2P2 = 60% decraesed, so it has, P2=60100×P

V1V_1V1 = V and V2V_2V2 incraesed by 50%, so it is, V2=1+50100×V=32×V
Plug in the values now,

T2 = P2V2P1V1

T2 =

P×V258=(35)P×(32)VT2

T2=258×3×P×3×V5×2×P×V

=232.2K


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