Question

If is found, on heating a gas, its volume increase by 50% and pressure decreases to 60% of its original value. If the original temperature was−15∘C, find the temperature to which is was heated?

Solution

The gas has constant mass as it is ideal. So we can use the equation for the general transformation of the ideal gas:

The mixed gas formula: P1V1T1=P2V2T2

Given: T1 = -15°C+273 = 258 K

Assume: P1 = 1 atm and P2 = 60% decraesed, so it has, P2 = 0.4 atm

V1 = 1 L and V2 incraesed 50%, so it is, V2 = 1.5 L

Plug in the values now,

T2 = P2V2T1P1V1

T2 = 0.4atm×1.5L×258K1atm×1L

= 193.5 K

= 193.5 - 273 = -79.5°C

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