CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If K1and K2 are the respective equilibrium constants for the two reactions
XeF6(g)+H2O(g)XeOF4(g)+2HF(g)

XeO4(g)+XeF6(g)XeOF4(g)+XeO3F2(g)
the equilibrium constant of the following reaction is:

XeO4(g)+2HF(g)XeO3F2(g)+H2O(g) will be:

A
K1/K22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
K1×K2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
K1/K2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
K2/K1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D K2/K1
For the reaction
XeF6(g)+H2O(g)XeOF4(g)+2HF(g)
K1=[XeOF4][HF]2[XeF6][H2O] . . . . . (1)
and for the reaction
XeO4(g)+XeF6(g)XeOF4(g)+XeO3F2(g)

K2=[XeOF4][XeO3F2][XeO4][XeF6] . . . . . (2)
For reaction :
XeO4(g)+2HF(g)XeO3F2(g)+H2O(g)

K=[XeO3F2][H2O][XeO4][HF]2...
Clearly, from (I) and (2) K=K2/K1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon