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Question

If Kw for pure H2O at 45C is 4×1014 M2. The pH of water at this temperature is :


A
5.7
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B
3.7
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C
4.7
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D
6.7
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Solution

The correct option is C 6.7
We know that,
Kw=[H+] [OH]
As water is neutral and for a neutral solution:
[H+]=[OH]Kw=[H+]2Kw=4×1014   (Given)[H+]2=4×1014     [H+] =4×1014=2×107pH=log10[H+]pH=log10(2×107)pH=(0.37)pH=6.7

Chemistry

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