If λ0 and λ be the threshold wavelength and the wavelength of incident light respectively, the velocity of photo-electrons ejected from the metal surface is:
A
√2hm(λ0−λ)
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B
√hm(λ0−λ)
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C
√2hcm(λ0−λλλ0)
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D
√2hcm(1λ0−1λ)
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Solution
The correct option is C√2hcm(λ0−λλλ0) As per Einstein's equation of photoelectric effect hν=hν0+K.E.
Where, ν=frequency of incident radiation νo=thresholdfrequency ∴12mv2=hν−hν0=hcλ−hcλ0 v2=2hcm(1λ−1λ0) ⇒v=[2hcm(1λ−1λ0)]1/2 ⇒v=[2hcm(λ0−λλλ0)]1/2