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Question

If (1i1+i)96=a+ib, then (a,b) is
 
  1. (1,1)  
  2. (1,0)    
  3. (0,1)    
  4. (0,1)   


Solution

The correct option is B (1,0)    
1i1+i=(1i)2(1+i)(1i)
=2i2=i
(1i1+i)96=(i)96=(i4)24=1=1+i0
(a,b)=(1,0)

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