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Question

If |z25i|15 then | maximum amp (z) minimum amp (z)| is equal to

A
sin1(35)cos1(35)
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B
π2+cos1(35)
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C
π2cos1(35)
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D
cos1(35)
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Solution

The correct option is C π2cos1(35)
We have maximum.amp(z)==amp(z2)
mini.amp(z)=amp(z1)
Now amp(z1)=θ1=cos11525=cos135
and amp(z2)=π2+θ2=π2+sin11525=π2+sin135
So |max.amp(z)mi.amp(z)|=π2+sin135cos135
=π2+π22cos135=π2cos135

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