CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If log0.5sinx=1log0.5cosx, then the number of solutions in the interval [2π,2π] is

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4
log0.5sinx=1log0.5cosxlog0.5sinxcosx=1
sinxcosx=0.5sin2x=12x=nπ+(1)nπ2
number of solutions is 4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon