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Question

If log0.5 (x1)<log0.25 (x1), then x lies in the interval.


A

(2,)

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B

(3,)

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C

(,0)

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D

(0, 3)

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Solution

The correct option is A

(2,)


log0.5 (x1)<log0.25 (x1)log0.5 (x1)<log(0.5)2 (x1)=log0.5 (x1)log0.5 (0.5)2 =12log0.5 (x1)log0.5 (x1)<0x1>1xϵ(2,)


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