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Question

# If log1/√2(1/√8)=log2(4x+1).log2(4x+1+4), then x=.................

A
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B
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C
2
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D
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Solution

## The correct option is D 0Given: log1/√2(1/√8)=log2(4x+1).log2(4x+1+4)⇒log1/√2(1/√2)3=log2(4x+1).log2(4x+1+4)⇒3=log2(4x+1).log2(4x+1+4)Since product of two no is 3, so one number will be 1 and other number will be 3.⇒1×3=log2(4x+1).log2(4x+1+4)Case 1: log2(4x+1)=1⇒4x+1=2⇒4x=1⇒x=0Now for x=0; second number should be 3.So,log2(4x+1+4)=log2(40+1+4)=log28=3Hence, x=0 is satisfy the above equation.

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