Question

If $(m+n{)}^{th}$ term of a G.P. is 9 and $(m-n{)}^{th}$ term is $4$, then $m^{th}$ term will be

• A. $6$
• B. $\frac{1}{6}$
• C. $6.5$
• D. None of these

Answer 1

The correct option is A $6$

As we know each term is G.P. is geometric mean of the terms equidistant from it.
Here $(m+n{)}^m$ and $(mn{)}^m$ terms are equidistant
So therefore $m^m$ term will be G.M. of $(m+n{)}^m$ and
$(mn{)}^{m}i.e.\sqrt{mn}=\sqrt{9\times 4}=6$