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Question

If A=0 23-4 and kA= 03a2b24, then the values of k, a, b, are respectively
(a) −6, −12, −18
(b) −6, 4, 9
(c) −6, −4, −9
(d) −6, 12, 18

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Solution

(c) −6, −4, −9


Given: A=023-4Here,kA=03a2b24k023-4=03a2b2402k3k-4k=03a2b24The corresponding elements of two equal matrices are equal.2k=3a, 3k=2b and-4k=24 Now,-4k=24 k=-6Also, 2k=3a and 3k=2b2-6=3a and 3-6=2b Using k=-6-12=3a and -18=2b a=-4 and b=-9

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