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Question

If n1,n2 and n3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:
If n1 origin
  1. 1n=1n1+1n2+1n3
  2. 1n=1n1+1n2+1n3
  3. n=n1+n2+n3
  4. n=n1+n2+n3


Solution

The correct option is A 1n=1n1+1n2+1n3
n1=12l1Tμn2=12l2Tμn3=12l3Tμn=12lTμl=l1+l2+l31n=1n1+1n2+1n3

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