If n - 2- - 2550- n- find the value of n-

(n + 2)! = 2550× n! (n + 2)(n + 1)× (n!) = 51× 50× (n!) ⇒ (n + 2)(n + 1) = 51 × 50 Comparing we get, ⇒ n + 1 = 50 ⇒ n = 49 . ...

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Factorial

If n + 2! =...

Question

If $(n + 2)! = 2550 \times n!$ , find the value of $n$ .

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(n + 2)! = 2550 \cdot n!

n

If $(n + 2)! = 2550 \times n!$ then the value of $n$ is equal to

n^{2} + n = 2

n .

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