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Question

If n is any positive integer, write the value of i4n+1i4n12

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Solution

i4n+1i4n12=i4n×i1i4n×i12=(i4)n×i(i4)n×1i2=1×i11i×i×i2=iii22=i+i2 ( i2=1)=2i2=i


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