If (N,P,As) was Dobereiner's triads then what would be the absolute error in atomic mass of phosphorous as compared to the original mass? Atomic mass : Nitrogen =14 amu, Arsenic =74.9 amu, Phosphorous =31 amu
A
13.45
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B
12.45
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C
15.55
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D
16.55
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Solution
The correct option is A13.45 We assume that N, P, As follow the Dobereiner's triads. It follows that M(P)=(M(N)+M(As))2 M(P)=(14+74.9)2=44.45 Absolute error in mass of phosphorous =44.45−31=13.45