If nP 4-7920- Find nC4-A- 120B- 220C- 330D- 660

The correct option is C 330Given, nP4 = 7920 nP4 = (n)×(n 1)×(n 2)×(n 4) = 7920 — gt; (1) nC4 = ((n)×(n 1)×(n 2)×(n 4))/ 1×2×3×4 Substituting (1) into ( ...

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Combination

If nP 4=7920,...

Question

If nP4 = 7920, Find nC4.

120

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220

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330

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660

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Solution

The correct option is C 330
Given, nP4 = 7920
$n P 4 = (n) \times (n - 1) \times (n - 2) \times (n - 4) = 7920 - - - - > (1) n C 4 = \frac{((n) \times (n - 1) \times (n - 2) \times (n - 4))}{1 \times 2 \times 3 \times 4} Substituting (1) into (2),$
nC4 = 7920/(1 $\times$ 2 $\times$ 3 $\times$ 4)
= 7920/24
= 330

Suggest Corrections

If nP4 = 7920, Find nC4.

The correct option is C 330Given, nP4 = 7920 nP4=(n)×(n−1)×(n−2)×(n−4)=7920−−−−>(1)nC4=((n)×(n−1)×(n−2)×(n−4))1×2×3×4Substituting(1)into(2), nC4 = 7920/(1×2×3×4) = 7920/24 = 330