Question

# If $$O$$ is centre of circle as shown in figure, find $$\angle RTO$$ if  $$\angle QRT=30^{\circ}$$

Solution

## The angles on the same line sum up to give $$180$$ $$\implies \angle POT+\angle TOQ=180\\\angle TOQ =180-140=40^{\circ}$$Consider $$\Delta RTO$$Sum of angles is $$180$$$$\implies 40+30+\angle RTO=180\\\angle RTO=110^{\circ}$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More