CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If ω is an imaginary cube root of unity then (1+ωω2)7 equals?

A
128ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
128ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
128ω2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 128ω2
Q. If ω is an imaginary. cube root of unity
then (1+ωω2)7 equals?
Soln as we know 1+ω+ω2=0 & ω3=1
now, (1+ωω2)7
=(ω2ω2)7
=(2ω2)7
=(2)7.ω14.(1)
=128.ω14.ω3
=128.ω17
=128.(ω3)5.ω2
(1+ωω2)7=128ω2

1178724_1071206_ans_d3dc7683cd3048d5b1e838e85ad9005b.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Convexity and Concavity
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon