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Question

If on giving 40 joulr of heat to a system, work done on the system is 10 joule, what will be the change in internal energy of rhe system.

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Solution

Dear student sign convention heat given to the system = +ve heat released by the system = -ve work done by the system = +ve work done on the system = -ve so, applying first law of thermodynamics dq=du+dw 40= du+(-10) du= 50 joule Regards

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