Question

# If one of the lines of $$my^{2}+(1-m^{2})xy-mx^{2}=0$$ is a bisector of the angle between the lines xy=0, then m=

A
-2
B
1
C
2
D
-1/2

Solution

## The correct option is B 1The bisectors of xy = 0 ie x = 0 and y = 0, we have are$$x+y = 0$$ and $$x-y = 0$$$$\Rightarrow$$ Now$$my^{2}+(1-m^{2})xy-mx^{2}= 0$$$$my^{2}+1xy-m^{2}xy - mx^{2} = 0$$$$my (my+x)-mx(my+x) = 0$$$$\Rightarrow (y-mx)(my+x) = 0$$on comparing there with x + y = 0 and x - y = 0 we have m = 1 Mathematics

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