If one of the zero of the quadratic polynomial $(k - 1) x^{2} + k x + 1$ is -3 then find the value of $k$ .

Open in App

Solution

We know that if $a$ is a zero of $f (x)$ then $f (a) = 0$
Since $- 3$ is a zero of the given polynomial
$∴ (k - 1) (- 3)^{2} + k (- 3) + 1 = 0$
$\Rightarrow 9 k - 9 - 3 k + 1 = 0 \Rightarrow k = \frac{4}{3}$

Suggest Corrections

Similar questions

\frac{- 5}{4}

\frac{5}{4}

\frac{- 4}{3}

\frac{4}{3}

(k - 1) x^{2} + k x + 1

(k - 1) x^{2} + k x + 1

(A) \frac{4}{3}

(B) \frac{- 4}{3}

(C) \frac{2}{3}

(D) \frac{- 2}{3}

If one of the zeros of quadratic polynomial (k - 1) x^{2} + k x + 1 is - 3,

then find the value of k .

Join BYJU'S Learning Program