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Question

If one of the zero of the quadratic polynomial $$(k - 1)x^2 + kx +1$$ is -3 then find the value of $$k$$.


Solution

We know that if $$a$$ is a zero of $$f(x)$$ then $$f(a) =0$$
Since $$-3$$ is a zero of the given polynomial 
$$\therefore (k - 1) (-3)^2 + k(-3) + 1 =0$$
$$\Rightarrow 9k - 9 - 3k + 1 = 0 \Rightarrow k =\frac{4}{3}$$

Mathematics

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