Question

# If one of the zeroes of the quadratic polynomial $$(k-1)x^{2}+kx+1$$ is $$-3$$, then the value of $$k$$ is.

A
43
B
43
C
23
D
23

Solution

## The correct option is A $$\dfrac{4}{3}$$Given $$-3$$ is the zero of the polynomial $$(k-1)x^2+ k x+1$$So $$-3$$ must satisfy the equation $$(k-1)x^2+k x+1=0$$$$\implies (k-1)(-3)^2+k(-3)+1=0$$$$\implies 9(k-1)-3 k+1=0$$$$\implies 9 k-9-3 k+1=0$$$$\implies 6 k=8$$$$\implies k=\dfrac{4}{3}$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More