Question

If one of the zeros of the cubic polynomial $a{x}^3+b{x}^2+cx+d$ is 0 then the product of the other two zeros is

(a) $\frac{-c}{a}$ (b) $\frac{c}{a}$ (c) 0 (d) $\frac{-b}{a}$

Answer 1

Given that, 0 is the zero of polynomial

∴ p (x) reduces to –

To find the zeros,

Put, p(x) = 0

Let α, β be the other zeros of p(x)

Then from (1), product of zeros is given by –

option b is correct