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Question

If one root of the equation x2+px+12=0~is~4,while the equation

x2+px+q=0 has equal roots, the value of q is


A

494

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B

449

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C

4

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D

none of these

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Solution

The correct option is A

494


It is given that, 4 is the root of the equation

x2+px+12=016+4p+12=0p=7

It is also given that, the equationx2+px+q=0has equal roots. So, the discriminant ofx2+px+q=0 will be zero. p24q=04q=(7)2=49q=494


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