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Question

If one root of the quadratic equation , $${x}^{2}-9x+k=0$$ is $$1$$, then find the value of $$k$$.


Solution

Given, one root of the quadratic equation $${x}^{2}-9x+k=0$$ is $$1$$
$$\therefore$$ Substituting $$x=1$$ in the given equation,
$$\therefore$$ $${x}^{2}-9x+k=0$$
$${(1)}^{2}-9(1)+k=0$$
$$\therefore$$ $$1-9+k=0$$
$$\therefore$$ $$-8+k=0$$
$$\therefore$$ $$k=8$$

Mathematics

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