Question

# If one root of the quadratic equation , $${x}^{2}-9x+k=0$$ is $$1$$, then find the value of $$k$$.

Solution

## Given, one root of the quadratic equation $${x}^{2}-9x+k=0$$ is $$1$$$$\therefore$$ Substituting $$x=1$$ in the given equation,$$\therefore$$ $${x}^{2}-9x+k=0$$$${(1)}^{2}-9(1)+k=0$$$$\therefore$$ $$1-9+k=0$$$$\therefore$$ $$-8+k=0$$$$\therefore$$ $$k=8$$Mathematics

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